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4y+2+(y^2-6y+5)=2
We move all terms to the left:
4y+2+(y^2-6y+5)-(2)=0
We add all the numbers together, and all the variables
4y+(y^2-6y+5)=0
We get rid of parentheses
y^2+4y-6y+5=0
We add all the numbers together, and all the variables
y^2-2y+5=0
a = 1; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·1·5
Δ = -16
Delta is less than zero, so there is no solution for the equation
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